This semester, I am teaching “Algebra II” for the first time. After “Algebra I” which covers standard “Groups, rings and fields”, this follow-up is largely Galois theory. In particular, I have to classify cyclic extensions.
In the simplest case where
is a cyclic extension of degree
and
contains all
-th roots of unity (and
is coprime to the characteristic of
), this essentially means proving that if
has cyclic Galois group of order
, then there is some
with
and
belongs to
.
Indeed, the converse is relatively simple (in the technical sense that I can do it on paper or on the blackboard without having to think about it in advance, by just following the general principles that I remember).
I had however the memory that the second step is trickier, and didn’t remember exactly how it was done. The texts I use (the notes of M. Reid, Lang’s “Algebra” and Chambert-Loir’s delightful “Algèbre corporelle”, or rather its English translation) all give “the formula” for the element
but they do not really motivate it. This is certainly rather quick, but since I can’t remember it, and yet I would like to motivate as much as possible all steps in this construction, I looked at the question a bit more carefully.
As it turns out, a judicious expansion and lengthening of the argument makes it (to me) more memorable and understandable.
The first step (which is standard and motivated by the converse) is to recognize that it is enough to find some element
in
such that
, where
is a generator of the Galois group
and
is a primitive
-th root of unity in
. This is a statement about the
-linear action of
on
, or in other words about the representation of
on the
-vector space
. So, as usual, the first question is to see what we know about this representation.
And we know quite a bit! Indeed, the normal basis theorem states that
is isomorphic to the left-regular representation of
on the vector space
of
-valued functions
, which is given by
.
(It is more usual to use the group algebra
, but both are isomorphic).
The desired equation implies (because
is generated by
) that
is a sub-representation of
. In
, we have an explicit decomposition in direct sum

where
runs over all characters
(these really run over all characters of
over an algebraic closure of
, because
contains all
-th roots of unity and
has exponent
). So
(if it is to exist) must correspond to some character. The only thing to check now is whether we can find one with the right
eigenvalue.
So we just see what happens (or we remember that it works). For a character
such that
, and
the element corresponding to
under the
-isomorphism
, we obtain
. But by easy character theory (recall that
is cyclic of order
) we can find
with
, and we are done.
I noticed that Lang hides the formula in Hilbert’s Theorem 90: an element of norm
in a cyclic extension, with
a generator of the Galois group, is of the form
for some non-zero
; this is applied to the
-th root of unity in
. The proof of Hilbert’s Theorem 90 uses something with the same flavor as the representation theory argument: Artin’s Lemma to the effect that the elements of
are linearly independent as linear maps on
. I haven’t completely elucidated the parallel however.
(P.S. Chambert-Loir’s blog has some recent very interesting posts on elementary Galois theory, which are highly recommended.)